kuiz
[tex] \\ [/tex]
[tex] \sf \large{4u - 8( \frac{2}{6} ) + {}^8 \log \: 32= 48}[/tex]
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[tex] \\ [/tex]
[tex] \sf \large{4u - 8( \frac{2}{6} ) + {}^8 \log \: 32= 48}[/tex]
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Jawaban:
[tex]4u \: - 8 ( \frac{2}{6} ) + log_{8}(32) = \: 48 \\ \\ 4u \: - \: \frac{8}{3} + \frac{5}{3} = 48 \\ \\ 4u \: - \frac{3}{3} = 48 \\ 4u \: - 1 = 48 \\ 4u \: = 1 + 48 \\ 4u \: = \: 49 \\ u \: = \frac{49}{4 } \\ u \: = \: ( \frac{7}{2} )^{2} [/tex]
[tex]\purple{\boxed{\green{\boxed{\red{\tt{\ \: \red{{ ༻ シ︎XxDAЯКNESSxXツ ༺ }}}}}}}}[/tex]
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